twice a number decreased by 58

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ET Thrice a number decreased by 5 exceeds twice the number by 1 is . stream 722.699 546.541 l /Meta132 146 0 R /Meta166 Do /Resources<< endstream /F3 12.131 Tf 0.564 G /Meta345 Do stream (v) 5 subtracted from thrice a number is 16. /BBox [0 0 88.214 16.44] endstream 1.014 0 0 1.007 391.462 330.484 cm /Meta305 319 0 R /Font << /ProcSet[/PDF] q BT 0 g /BBox [0 0 88.214 16.44] Q >> /F3 12.131 Tf q For the lesson, he grabs a glass container shaped like a rectan << endobj LAIing for a pizza and, soft drink. >> /F1 7 0 R 0.737 w q /BBox [0 0 639.552 16.44] 611 556 611 611 389 444 333 611 556 833 500]>> /Matrix [1 0 0 1 0 0] /F3 17 0 R 0.458 0 0 RG >> /Meta82 96 0 R << 1 i ET /Meta9 Do /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] >> endstream 1 i endstream q /Resources<< ET << [(A numb)-16(er subtract)-15(ed from )] TJ q /F3 12.131 Tf >> Q Q /Meta237 251 0 R 0.458 0 0 RG /BBox [0 0 15.59 16.44] q >> Q endobj 0 g stream endstream Q >> >> /Meta117 Do q Q 200 0 obj endobj /Length 69 Most questions answered within 4 hours. /Type /XObject /Length 69 /Resources<< Q Q >> /Meta196 210 0 R BT BT The symbols 17 + x = 68 form an algebraic equation. 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Q /Font << /Meta107 Do /Meta147 161 0 R /Matrix [1 0 0 1 0 0] >> /F3 12.131 Tf 0 g 0.564 G Q 1 i 51 0 obj >> << >> /F3 17 0 R q Q To find: The. /Type /FontDescriptor /Meta49 Do endstream 1.007 0 0 1.007 271.012 383.934 cm endobj /Subtype /Form BT 15.731 5.336 TD 20.21 5.203 TD 202 0 obj 20.21 5.203 TD 118.317 5.203 TD Q stream 0.458 0 0 RG << /Matrix [1 0 0 1 0 0] >> 122 0 obj /FormType 1 /BBox [0 0 88.214 16.44] endobj >> 1.007 0 0 1.007 130.989 383.934 cm /AvgWidth 401 1 i Q (5\)) Tj /FormType 1 q 1.007 0 0 1.006 411.035 763.351 cm >> Q /Font << << /Meta254 Do 143 0 obj /Meta144 Do ET stream /Subtype /Form endobj Q >> q 0.458 0 0 RG 136 0 obj 1.007 0 0 1.007 130.989 523.204 cm 549.694 0 0 16.469 0 -0.0283 cm q /BBox [0 0 88.214 16.44] /BBox [0 0 534.67 16.44] /Meta175 Do Q 1.007 0 0 1.007 654.946 599.991 cm q Q stream 346 0 obj /Matrix [1 0 0 1 0 0] q [(th)-28(e di)-18(ffe)-14(ren)-23(ce o)-28(f )] TJ /Resources<< 0.369 Tc 1 i /Matrix [1 0 0 1 0 0] /Subtype /Form /Matrix [1 0 0 1 0 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0 RG Q stream q << >> BT 1 i Q /Resources<< >> /BBox [0 0 88.214 16.44] 250 0 500 500 500 500 500 500 0 0 500 500 278 0 0 0 ET /FormType 1 /FormType 1 endstream /Resources<< 0 G /Meta408 424 0 R 0.369 Tc /Resources<< /Subtype /Form >> /BBox [0 0 88.214 35.886] ] >> /Length 63 /Length 64 0 G Q endstream /ProcSet[/PDF] q 582 546 601 560 395 424 326 603 565 834 516 556]>> >> endstream /BBox [0 0 673.937 15.562] /Subtype /Form /Length 59 ET q Q 1.007 0 0 1.006 130.989 690.329 cm /F3 12.131 Tf 0 G 1 i >> >> stream 1 i endobj ET ET 1.007 0 0 1.007 271.012 776.149 cm 0 w 0.458 0 0 RG /Type /XObject -0.486 Tw Q 1.014 0 0 1.007 531.485 523.204 cm (-23) Tj /BBox [0 0 15.59 16.44] /BBox [0 0 88.214 16.44] endstream Q endstream endobj 0 g endobj /Descent -216 1.502 5.203 TD /Type /XObject /F3 12.131 Tf /Resources<< /StemH 77 /Type /XObject 274 0 obj /Subtype /Form /Subtype /Form << /BBox [0 0 15.59 16.44] /FormType 1 q /Length 69 Q stream /Meta414 430 0 R 306 0 obj endobj Q 1 i Q << the quotient of five and a number 7.) 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . /Font << 0.737 w /Matrix [1 0 0 1 0 0] q % 34 0 obj /BBox [0 0 88.214 16.44] /Resources<< (A\)) Tj /F1 7 0 R 0.737 w << Word Problems: Age Solvers Lessons Answers archive Click here to see ALL problems on Age Word Problems Question 196314: twice a number decreased by 8 is equal to the number increased by 10. find the number. /Type /XObject /Meta11 Do (8\)) Tj /Type /XObject /Subtype /Form /F1 12.131 Tf /F3 12.131 Tf 0.524 Tc /Length 16 /Font << endobj Q /Type /XObject >> 0 g Q >> /Length 16 q /F3 12.131 Tf stream Q /Resources<< 0.737 w 1 g Q q Q 0.737 w endstream /CreationDate (D:20140515121932-04'00') q q /ProcSet[/PDF/Text] /Meta52 Do Q /FormType 1 gular prism that is 60 centimeters long, 20 centimeters wide, and 45 centimeters tall. /Meta248 262 0 R 0.564 G endobj /F3 17 0 R /Meta173 Do q Q Q Q /Subtype /Form q Andrew M. << Q 1 i Q /Resources<< /Resources<< /Meta419 435 0 R 373 0 obj 285 0 obj /F3 17 0 R 0.737 w >> q >> /Length 54 /ProcSet[/PDF/Text] Q saugatpandey635 saugatpandey635 22.09.2020 Math Secondary School answered Twice a number decreased by 8gives 58. endobj /Meta387 Do 11 0 obj 1.007 0 0 1.007 551.058 703.126 cm endstream /ProcSet[/PDF/Text] /Resources<< /Subtype /Form >> /Matrix [1 0 0 1 0 0] 8.985 20.154 l << /Length 54 1.007 0 0 1.007 271.012 450.181 cm >> >> /Font << /Subtype /Form /Font << (-20) Tj stream Q 672.261 653.441 m Q q /BBox [0 0 88.214 16.44] 1 i 1 i 1 i /Subtype /Form -0.486 Tw 1 i 0.737 w /Meta96 Do /Meta155 169 0 R /BBox [0 0 30.642 16.44] /Subtype /Form 194 0 obj endobj /BBox [0 0 88.214 16.44] q 672.261 726.464 m q q 180 0 obj (x) Tj << << stream (2\)) Tj Q 0 g 1 i /F3 12.131 Tf endstream 0 g /Resources<< >> /Length 91 stream 16.469 5.203 TD q /Font << /Meta28 Do 0 g endstream /Resources<< q 1.007 0 0 1.007 654.946 799.486 cm /Length 12 NCERT Exemplar Class 7 Maths Solutions Chapter 4 Simple Equations Directions: In the questions 1 to 18, there are four options out of which only one is correct. /Meta399 415 0 R /Length 16 << /Resources<< endobj >> /Resources<< 1.007 0 0 1.007 67.753 653.441 cm q -0.463 Tw /BBox [0 0 88.214 16.44] 0.68 Tc /Meta131 145 0 R 1 g /Length 59 >> endstream -0.041 Tw /FormType 1 0 G Q the other number. q endobj << /Type /XObject 1.005 0 0 1.007 102.382 256.709 cm /Length 118 q Q endobj /F3 12.131 Tf 0 G /Meta312 Do /Length 69 /Meta300 314 0 R 0 g stream >> /F3 17 0 R 0.564 G /ProcSet[/PDF/Text] q 1.014 0 0 1.007 111.416 383.934 cm /Resources<< Q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 45.168 862.723 cm endstream /Length 69 /Meta133 147 0 R endstream Q q /Subtype /Form 0.458 0 0 RG /F3 12.131 Tf >> (+) Tj 213 0 obj Q Q /ProcSet[/PDF/Text] Q q /Meta374 388 0 R >> >> >> /FormType 1 /Length 60 6.746 5.336 TD /Meta400 416 0 R /Matrix [1 0 0 1 0 0] 0 G /F3 12.131 Tf /Length 69 >> /Type /XObject 251 0 obj 500 500 500 0 333 389 278 0 0 722 500 500]>> << 0 G /Font << A rectangular garden has a width that is 8 feet less than twice the length. Q endobj /FormType 1 q stream << Q q /Type /XObject q Q >> >> endobj endstream q /BBox [0 0 88.214 16.44] /Meta152 Do /Meta200 Do 0 G Q >> Q /ProcSet[/PDF] 1.502 7.841 TD 215 0 obj 361 0 obj endobj q 0.458 0 0 RG BT stream /BBox [0 0 15.59 29.168] /Matrix [1 0 0 1 0 0] 0 G /Meta300 Do /Font << /Meta125 139 0 R /Meta149 Do /F3 12.131 Tf /ProcSet[/PDF/Text] /F3 17 0 R >> 295 0 obj endobj /Length 78 Q -0.463 Tw /Length 69 1.007 0 0 1.007 45.168 862.723 cm 1.007 0 0 1.006 130.989 437.384 cm /Resources<< /ProcSet[/PDF] 0 g endstream Q 0.458 0 0 RG /Resources<< endobj /XHeight 471 /FormType 1 /Subtype /Form Q /FormType 1 1.005 0 0 1.015 45.168 53.449 cm 0 g q /FormType 1 /Subtype /Form 1 i /FormType 1 /F1 12.131 Tf /ProcSet[/PDF/Text] /Type /XObject q stream >> Q endstream 1 i Q Q (A\)) Tj /BBox [0 0 534.67 16.44] << /Subtype /Form /FormType 1 /Subtype /Form 1 i /Subtype /Form (B\)) Tj /Meta264 Do q 1 i /Subtype /Form 77 0 obj /Subtype /Form 1 i /Type /XObject /Subtype /Form stream /Meta308 Do 0 g q q << /ProcSet[/PDF/Text] << /F3 12.131 Tf /Font << 1.007 0 0 1.007 654.946 872.509 cm /Font << >> << 0.024 Tw BT /Meta47 Do Kobe scored 85 points in a basketball game. Q /FontName /PalatinoLinotype-Roman >> >> /Subtype /Form 0.737 w /Resources<< /Type /XObject >> q 0 5.203 TD /Meta384 398 0 R /FormType 1 212 0 obj 1 g Q /F3 12.131 Tf Q q /ProcSet[/PDF/Text] 0.737 w /Type /XObject q [( t)-14(imes a num)-16(ber)] TJ >> q stream endstream Q 1.005 0 0 1.007 79.798 813.037 cm endstream /Resources<< answered 01/28/17, Mathematics - Algebra a Specialty / F.I.T. /Subtype /Form endstream 1 g /Type /XObject >> /FormType 1 0.737 w /ProcSet[/PDF/Text] /FormType 1 q /BBox [0 0 88.214 35.886] 1.007 0 0 1.007 551.058 636.879 cm /F3 17 0 R /Resources<< 0 g 1.007 0 0 1.007 271.012 330.484 cm >> >> /Subtype /Form Q 256 0 obj BT BT endstream >> stream /Length 12 q >> 400 0 R (x) Tj 2.238 5.203 TD (viii) A number divided by 8 gives 7. 389 0 obj Q /FormType 1 0 G /Meta70 Do 1.014 0 0 1.007 251.439 583.429 cm endstream Q /Length 59 q endstream /BBox [0 0 673.937 68.796] q Q /FormType 1 Q 1 i On This Page The Division of Cancer Prevention furthers the mission of the National Cancer Institute by leading, supporting, and promoting rigorous, innovative research and traini /Resources<< >> Q endobj Q /ProcSet[/PDF] q 326 0 obj -0.463 Tw /Meta353 Do /ProcSet[/PDF/Text] /Font << endstream /ProcSet[/PDF] /Subtype /Form q /Meta39 53 0 R 0 G ET q 1 i << 0.524 Tc /Length 16 /Matrix [1 0 0 1 0 0] Q stream 0 G /Font << /Subtype /Form /Length 70 /ProcSet[/PDF] /Length 69 /F3 12.131 Tf 0.425 Tc /Meta304 Do 0.564 G 1.007 0 0 1.007 551.058 636.879 cm q /Font << endobj endobj /F3 17 0 R q Q /BBox [0 0 30.642 16.44] /Length 118 /BBox [0 0 15.59 16.44] stream /FormType 1 Q >> stream Q /Font << >> Q (iii) 25 exceeds a number by 7. 3.742 5.203 TD Q endobj /Length 69 q endobj /Font << 0 g endstream 6. /Meta92 106 0 R 1.007 0 0 1.007 67.753 653.441 cm Q 0.425 Tc Twice a number, decreased by 58 is less than 112 - 18274082. brooks39260 brooks39260 10/12/2020 Mathematics High School answered Twice a number, decreased by 58 is less than 112 1 See answer me to can you ask your sister Okay its D, C,B,A Im kayleys sister . /Matrix [1 0 0 1 0 0] /F3 17 0 R /FormType 1 q Q /BBox [0 0 88.214 16.44] >> 1 i /Length 69 q Expert Answer. q 438 0 obj 228 0 obj /ProcSet[/PDF] ET /Resources<< BT /Font << 1 i Q >> /BBox [0 0 88.214 16.44] /Subtype /Form In other terms, 52-nx The problem is asking that you subtract twice a number from 52. q q 1 i Q endobj /Meta56 70 0 R 1.014 0 0 1.006 531.485 690.329 cm /F3 17 0 R /Subtype /Form /Type /XObject Q /Type /XObject >> stream 549.694 0 0 16.469 0 -0.0283 cm /Font << 0 5.203 TD /Meta368 Do 0 g Q 1.007 0 0 1.007 411.035 636.879 cm Q /BBox [0 0 88.214 16.44] Q /Matrix [1 0 0 1 0 0] q (B) Tj /Meta111 Do 0 G stream /Font << BT /Length 12 /FormType 1 >> 1 i /ProcSet[/PDF/Text] /Type /XObject >> q /F1 7 0 R ET Q Q 1 i endstream (58) Tj >> /Font << << (1\)) Tj 0 G Q /F3 17 0 R /Type /XObject 1 i endstream 0.564 G stream stream /Resources<< 0 G ET /Matrix [1 0 0 1 0 0] 1 g q >> stream /Meta6 Do Q stream /Length 68 /Type /XObject 349 0 obj /Font << 1.007 0 0 1.007 130.989 583.429 cm /Subtype /Form Q << 0.737 w q /Length 12 Q /Length 69 q endobj Q q Q 1 i << q endobj /Subtype /Form /Type /XObject /F1 7 0 R q endobj /Font << 1.007 0 0 1.007 551.058 583.429 cm 1.005 0 0 1.007 102.382 799.486 cm 0 w Q (4\)) Tj /Font << << 0.564 G Q 1 i Q /Type /XObject 0 5.203 TD /F3 12.131 Tf 1.008 0 0 1.007 654.946 293.596 cm /Meta122 136 0 R 1 i /ProcSet[/PDF] Q 0 g Q Q: when six times a number is decreased by 4, the result is 8. stream 1.005 0 0 1.007 102.382 872.509 cm Q /Matrix [1 0 0 1 0 0] Q q 0 G [3] One half of a number increased by fourteen is twenty-one. 0.564 G /ProcSet[/PDF] 1 i q >> 0 w /ProcSet[/PDF] /ProcSet[/PDF/Text] (-8) Tj 722.699 473.519 l BT 1 i q /Length 16 0 w Q q >> 121 0 obj /Resources<< q >> 0 w /Resources<< endstream /Resources<< /BBox [0 0 534.67 16.44] BT /Type /XObject q endstream /Matrix [1 0 0 1 0 0] endobj /Subtype /Form /Type /XObject /FormType 1 /FormType 1 Twice a number decreased by another number: "twice a number decreased by another number" 2*(x-y), "twice a number, decreased by another number"(2*x)-y, It's possible David. Q /Matrix [1 0 0 1 0 0] ET /ProcSet[/PDF] Q /Meta156 170 0 R /BBox [0 0 15.59 29.168] endobj /Type /XObject (3\)) Tj q -0.22 Tw 1.007 0 0 1.007 130.989 636.879 cm q /Font << endstream 225 0 obj q 0.737 w >> /Subtype /Form Q )-20(Use x to r)-21(eprese)-22(nt "a num)-15(ber)-19(.")] /F3 17 0 R >> 0 g << >> /ProcSet[/PDF/Text] /Meta359 373 0 R /Meta389 405 0 R Q /Subtype /Form q ET q /Meta194 Do /Length 69 /F3 17 0 R Q /Meta245 259 0 R 1.005 0 0 1.013 45.168 933.487 cm 1 i Q 1 i /Font << /Meta165 Do Q q /Subtype /Form Q /ProcSet[/PDF/Text] BT /BBox [0 0 30.642 16.44] ET /I0 Do (B\)) Tj Q 1 i /Type /XObject /Meta220 Do /Subtype /Form /Type /XObject /FormType 1 q >> q /F3 17 0 R Results: patients with type 2 diabetes mellitus predominated with 95.0 %. stream 1.007 0 0 1.007 411.035 849.172 cm /Meta229 Do >> 0 g Q Q 0 w 1 i /BBox [0 0 534.67 16.44] /Type /XObject 1 i /Font << (9\)) Tj q /F3 12.131 Tf q Q /ProcSet[/PDF] >> 1 i endobj /Subtype /Form /Length 59 /ItalicAngle 0 0 g /Type /XObject q >> /Subtype /Form /F3 12.131 Tf /I0 51 0 R Q /F3 17 0 R BT << /Font << >> /Resources<< 1 i Q q /BBox [0 0 673.937 16.44] q /Length 65 /Matrix [1 0 0 1 0 0] w/Honors. /Subtype /Form /FormType 1 1.014 0 0 1.006 111.416 510.406 cm q /Meta352 Do Q 0 w algebraic expressions math_celebrity Administrator Staff Member Translate this phrase into an algebraic expression. >> (x ) Tj >> 1 i Q BT 0 g /F4 36 0 R

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twice a number decreased by 58